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NEW QUESTION: 1
TOGAF規格は、カタログ、マトリックス、および図として次のどれを分類しますか？
A. ビルディングブロック
B. アーティファクト
C. アプリケーションプラットフォームインターフェイス
D. フレームワーク
E. 成果物
Answer: B
NEW QUESTION: 2
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:
You need to determine the total number of customers who have either deposit accounts or loan accounts, but not both types of accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION ALL
SELECT CustNo
FROM tblLoanAcct) R
B. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
EXCEPT
SELECT CustNo
FROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL OR L.CustNo IS NULL
D. SELECT COUNT (DISTINCT D.CustNo)
FROM tblDepositAcct D, tblLoanAcct L
WHERE D.CustNo = L.CustNo
E. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION
SELECT CustNo
FROM tblLoanAcct) R
F. SELECT COUNT(DISTINCT L.CustNo)
FROM tblDepositAcct D
RIGHT JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL
G. SELECT COUNT(*)
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
H. SELECT COUNT(*)
FROM (SELECT AcctNo
FROM tblDepositAcct
INTERSECT
SELECT AcctNo
FROM tblLoanAcct) R
Answer: C
Explanation:
Explanation/Reference:
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx
NEW QUESTION: 3
재고 관리와 관련하여 일반적으로 주문 빈도가 증가합니다.
A. 총 주문 비용을 줄입니다.
B. 총 운송 비용을 줄입니다.
C. 총 운송 비용에는 영향을 미치지 않습니다.
D. 총 주문 비용에 영향을 미치지 않습니다.
Answer: B
Explanation:
Inventory carrying costs can sometimes be transferred to suppliers. If a seller has good enough control of demand schedules to know exactly when goods are needed, orders can be placed so that goods arrive no earlier than when actually needed. This practice relies on a supplier who is willing to take the responsibility for storing the needed inventory and shipping it to arrive on time. Suppliers are more willing to provide this type of service when they have many competitors.