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NEW QUESTION: 1
CORRECT TEXT

Answer:
Explanation:
Router>enable
Router#config terminal
Router(config)#hostname Apopka
2) Enable-secret password (cisco10):
Apopka(config)#enable secret cisco10
3) Set the console password to RouterPass:
Apopka(config)#line console 0
Apopka(config-line)#password RouterPass
Apopka(config-line)#login
Apopka(config-line)#exit
4) Set the Telnet password to scan90:
Apopka(config)#line vty 0 4
Apopka(config-line)#password scan90
Apopka(config-line)#login
Apopka(config-line)#exit
5) Configure Ethernet interface (on the right) of router Apopka:
The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can
find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111
1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the
formula:
Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment
= 25 = 32. Therefore:
Increment: 32
Network address: 209.165.201.0
Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the
previous IP - 209.165.201.31 - is the broadcast address of the first subnet).
-> The second assignable host address of this subnetwork is 209.165.201.2/27
Assign the second assignable host address to Fa0/0 interface of Apopka router:
Apopka(config)#interface Fa0/0
Apopka(config-if)#ip address 209.165.201.2 255.255.255.224
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
6) Configure Serial interface (on the left) of router Apopka:
Using the same method to find out the increment of the Serial network:
Serial network 192.0.2.128/28:
Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address
of this subnet)
Broadcast address: 192.0.2.143
-> The last assignable host address in this subnet is 192.0.2.142/28.
Assign the last assignable host address to S0/0/0 interface of Apopka router:
Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful)
Apopka(config-if)#ip address 192.0.2.142 255.255.255.240
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
7) Configure RIP v2 routing protocol:
Apopka(config)#router rip
Apopka(config-router)#version 2
Apopka(config-router)#network 209.165.201.0
Apopka(config-router)#network 192.0.2.128
Apopka(config-router)#end
Save the configuration:
Apopka#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!

NEW QUESTION: 2
Scenario: A Citrix Engineer is managing an existing XenDesktop and Workspace Environment Management (WEM) infrastructure. The engineer performed recent benchmarks on all the user applications. As a result of this investigation, the engineer determined that some applications are consuming excess memory even when they are idle and NOT actively being utilized by users. This results in performance degradation of active applications.
Which step can the engineer take to help improve the performance degradation of active applications?
A. Enable Working Set Optimization and Exclude Specified Processes.
B. Enable Process I/O Priority and add Specified Processes.
C. Enable Working Set Optimization and set Idle State Limit to 10 minutes.
D. Enable Working Set Optimization and set Idle Sample Time to 10 minutes.
Answer: D
Explanation:
Explanation/Reference:
Reference: https://dreadysblog.wordpress.com/2016/11/07/10-20-seconds-login-times-with-citrix- workspace-environment-management/

NEW QUESTION: 3
Zeitliche Bedingungen können für Spalten der folgenden Datentypen definiert werden: Zeitstempel, Datum und Text.
Bestimmen Sie, ob diese Aussage wahr oder falsch ist.
A. Falsch
B. Richtig
Answer: A