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NEW QUESTION: 1
Sie haben eine Anwendung mit dem Namen App1. App1 wird auf mehrere virtuelle Hyper-V-Maschinen in einer Umgebung mit mehreren Mandanten verteilt.
Sie müssen sicherstellen, dass der Datenverkehr gleichmäßig auf die virtuellen Maschinen verteilt wird, auf denen App1 gehostet wird.
Was sollten Sie in die Umgebung einbeziehen?
A. Ein RAS-Gateway und ein Windows Server-NLB-Knoten (Network Load Balancing)
B. Ein RAS-Gateway und SLB-Knoten (Windows Server Software Load Balancing)
C. Network Controller- und Windows Server-NLB-Knoten (Network Load Balancing)
D. SLB-Knoten (Network Controller und Windows Server Software Load Balancing)
Answer: B
Explanation:
https://technet.microsoft.com/en-us/library/mt403307(v=ws.11).aspx#bkmk_slb
https://docs.microsoft.com/en-us/windows-server/networking/sdn/technologies/network-controller/network-controller#bkmk_gateway
NEW QUESTION: 2
Which flow shapes can be used to send an email? (Choose three)
A. Integrator
B. Utility
C. Send Email smart shape
D. Assignment
E. End
Answer: A,B,D
NEW QUESTION: 3
A. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
C. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
D. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
E. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
Answer: E
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php