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NEW QUESTION: 1
Which operating system is supported for an IBM Tivoli Storage Productivity Center V5.1 server installation?
A. Windows 2003 R2
B. AIX V5.3
C. RHEL 5
D. Windows 7
Answer: C
NEW QUESTION: 2
DRAG DROP
You manage a SharePoint environment.
You need to block all ports on the SharePoint Servers that are not used for essential communications.
To answer, drag the appropriate set of port ranges to the correct service. Each set of ports ranges may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
NOTE: Each correct selection is worth one point.
Select and Place:
Answer:
Explanation:
NEW QUESTION: 3
Refer to the exhibit. In this network, R1 has been configured to advertise a summary route, 192.168.0.0/22, to R2. R2 has been configured to advertise a summary route, 192.168.0.0/21, to R1. Both routers have been configured to remove the discard route (the route to null created when
a summary route is configured) by setting the administrative distance of the discard route to 255. What will happen if R1 receives a packet destined to 192.168.3.1 ?
A. The packet will be forwarded to R2, where it will be routed to null0.
B. The packet will loop between R1 and R2.
C. It is not possible to set the administrative distance on a summary to 255.
D. The packet will be dropped by R1, since there is no route to 192.168.3.1.
Answer: B
Explanation:
Indeed, when you change the administrative distance of the discard route to 255, this prevents the
route to be installed in the routing table but this does not prevent the route to be advertised to the
other peer!
From the Cisco website:
"You can configure a summary aggregate address for a specified interface. If there are any more
specific routes in the routing table, EIGRP will advertise the summary address out the interface
with a metric equal to the minimum of all more specific routes"
And don't forget YOU HAVE a directly connected route 192.168.1/24 in R1 and .4/24 in R2.
Then your summary is advertised, and the packet loop between R1 and R2.
If you do the test with GNS3, you will see via "show ip eigrp topology" that you FD of your local
subnet 192.168.1.0/24 in R1 become the metric of the summary route "192.168.0.0/22 advertise to
R2 ! And viceversa. Numerically, an administrative distance is an integer from 0 to 255. In general,
the higher the value, the lower the trust rating. An administrative distance of 255 means that the
routing information source cannot be trusted at all and should be ignored.
http://www.cisco.com/en/US/docs/ios/12_3/iproute/command/reference/ip2_c1g.html
A route with an AD of 255 would never be installed in the RIB. It is much better for the router to
forward a packet to null0 following the default route than for the router to find out it has no route to destination, drop the packet and probably to send an ICMP unreachable message back to the source of that packet.
https://supportforums.cisco.com/thread/192416 You should not use the ip summary-address eigrp summarization command to generate the default route (0.0.0.0) from an interface. This causes the creation of an EIGRP summary default route to the null 0 interface with an administrative distance of 5. The low administrative distance of this default route can cause this route to displace default routes learned from other neighbors from the routing table. If the default route learned from the neighbors is displaced by the summary default route, or if the summary route is the only default route present, all traffic destined for the default route will not leave the router, instead, this traffic will be sent to the null 0 interface where it is dropped.
http://www.cisco.com/en/US/docs/ios/12_0/np1/configuration/guide/1ceigrp.html#wp4937
Here are the configurations and CLI output to prove the answer is A.
This is done on IOS 12.4T train of code.
R1
interface Loopback0 ip address 192.168.1.1 255.255.255.0 ! interface FastEthernet0/0 ip address 10.1.2.1 255.255.255.0 ip summary-address eigrp 1 192.168.0.0 255.255.252.0 255
! router eigrp 1 network 10.0.0.0 network 192.168.1.0 no auto-summary R2
interface Loopback0 ip address 192.168.4.2 255.255.255.0 ! interface FastEthernet0/0 ip address 10.1.2.2 255.255.255.0 ip summary-address eigrp 1 192.168.0.0 255.255.248.0 255 ! router eigrp 1 network 10.0.0.0 network 192.168.4.0 no auto-summary Show Output
Look at R1 s routing table...notice it does NOT have the summary route to null0 for 192.168.0.0/22 because we have disabled it. It does have a summary route to 192.168.0.0/21 from R2 it is receiving... R1#show ip route | b Gateway Gateway of last resort is not set 10.0.0.0/24 is subnetted, 1 subnets C 10.1.2.0 is directly connected, FastEthernet0/0 C 192.168.1.0/24 is directly connected, Loopback0 D 192.168.0.0/21 [90/156160] via 10.1.2.2, 00:03:45, FastEthernet0/0 Now look at R2 s routing table. Notice it does NOT have a summary route to null0 for the 192.168.0.0/21 because we disabled it. It does however have a route for 192.168.0.0/22 received from R1. R2#sh ip route | b Gateway Gateway of last resort is not set C 192.168.4.0/24 is directly connected, Loopback0 10.0.0.0/24 is subnetted, 1 subnets C 10.1.2.0 is directly connected, FastEthernet0/0 D 192.168.0.0/22 [90/156160] via 10.1.2.1, 00:05:36, FastEthernet0/0 Now, what will happen? As I said -- When R1 pings 192.168.3.1 it will look in its routing table, and it will see the
EIGRP route 192.168.0.0/21 from R2 so it will send the packet to R2 since 192.168.3.1 is part of
that summary.
R2 will get the packet and look in its routing table. It will find an EIGRP route for 192.168.0.0/22
from R1 and route the packet back to R1 since 192.168.3.1 is within that summary range.
This continues in a loop until the IP TTL expires.
Traceroute from R1. Notice it goes to R2 then right back to R1...Hope this helps! ----------------
R1#trace 192.168.3.1
Type escape sequence to abort.
Tracing the route to 192.168.3.1
1 10.1.2.2 0 msec 0 msec 4 msec
2 10.1.2.1 0 msec 0 msec 4 msec 3 * * *
NEW QUESTION: 4
Which of the following are NOT a countermeasure to traffic analysis?
A. Faraday Cage
B. Padding messages.
C. Eavesdropping.
D. Sending noise.
Answer: C
Explanation:
Explanation/Reference:
Eavesdropping is not a countermeasure, it is a type of attack where you are collecting traffic and attempting to see what is being send between entities communicating with each other.
The following answers are incorrect:
Padding Messages. Is incorrect because it is considered a countermeasure you make messages uniform size, padding can be used to counter this kind of attack, in which decoy traffic is sent out over the network to disguise patterns and make it more difficult to uncover patterns.
Sending Noise. Is incorrect because it is considered a countermeasure, tansmitting non-informational data elements to disguise real data.
Faraday Cage Is incorrect because it is a tool used to prevent emanation of electromagnetic waves. It is a very effective tool to prevent traffic analysis.