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NEW QUESTION: 1
Click the Exhibit button. CREATE FUNCTION deptemployees (idept VARCHAR(3)) RETURNS TABLE (empno CHAR(6), firstnameVARCHAR(12), lastnameVARCHAR(15)) LANGUAGE SQL READS SQL DATA NO EXTERNAL ACTION DETERMINISTIC RETURN SELECT empno, firstnme, lastname FROM employee WHERE workdept = deptemployees.idept; Referring to the exhibit, what contains the proper way to invoke the DEPTEMPLOYEES() user-defined function to return all of the employees that work in department D11?
A. SELECT * FROM TABLE(deptemployees('D11'))
B. SELECT * FROMdeptemployees('D11') AS D11dept
C. SELECT * FROMdeptemployees('D11')
D. SELECT * FROM TABLE(deptemployees('D11')) AS D11dept
Answer: D
NEW QUESTION: 2
Refer to the exhibit. Which address and mask combination represents a summary of the routes learned by EIGRP?
A. 192.168.25.16 255.255.255.240
B. 192.168.25.28 255.255.255.252
C. 192.168.25.0 255.255.255.240
D. 192.168.25.0 255.255.255.252
E. 192.168.25.16 255.255.255.252
F. 192.168.25.28 255.255.255.240
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
+ 192.168.25.16
+ 192.168.25.20
+ 192.168.25.24
+ 192.168.25.28
-> The increment should bE. 28 ?16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24).
Therefore, the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) = 255.255.255.240 So the best answer should be 192.168.25.16 255.255.255.240
NEW QUESTION: 3
CORRECT TEXT
A network associate is configuring a router for the weaver company to provide internet access.
The ISP has provided the company six public IP addresses of 198.18.184.105 198.18.184.110.
The company has 14 hosts that need to access the internet simultaneously. The hosts in the
company LAN have been assigned private space addresses in the range of 192.168.100.17 - 192.168.100.30.
Answer:
Explanation:
The company has 14 hosts that need to access the internet simultaneously but
we just have 6 public IP addresses from 198.18.184.105 to 198.18.184.110/29.
Therefore we have to use NAT overload (or PAT)
Double click on the Weaver router to open it
Router>enable
Router#configure terminal
First you should change the router's name to Weaver
Router(config)#hostname Weaver
Create a NAT pool of global addresses to be allocated with their netmask.
Weaver(config)#ip nat pool mypool 198.18.184.105 198.18.184.110 netmask 255.255.255.248
Create a standard access control list that permits the addresses that are to be translated
Weaver(config)#access-list 1 permit 192.168.100.16 0.0.0.15
Establish dynamic source translation, specifying the access list that was defined in the prior step
Weaver(config)#ip nat inside source list 1 pool mypool overload
This command translates all source addresses that pass access list 1, which
means a source address from 192.168.100.17 to 192.168.100.30, into an
address from the pool named mypool (the pool contains addresses from 198.18.184.105 to 198.18.184.110)
Overload keyword allows to map multiple IP addresses to a single registered IP address (many-to-one) by using different ports
The question said that appropriate interfaces have been configured for NAT inside and NAT outside statements.
This is how to configure the NAT inside and NAT outside, just for your understanding:
Weaver(config)#interface fa0/0
Weaver(config-if)#ip nat inside
Weaver(config-if)#exit
Weaver(config)#interface s0/0
Weaver(config-if)#ip nat outside
Weaver(config-if)#end
Finally, we should save all your work with the following command:
Weaver#copy running-config startup-config
Check your configuration by going to "Host for testing" and type:
C :\>ping 192.0.2.114
The ping should work well and you will be replied from 192.0.2.114