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NEW QUESTION: 1
Which three of these software modules can you layer on top of LTM on a BIG-IP device?
A. ARX
B. APM
C. Web Accelerator
D. Firepass
E. Enterprice Manager
F. GTM
Answer: B,C,F
Explanation:
Thesesoftware modules can you layer on top of LTM on a BIG-IP device are AAM, APM and GTM.
NEW QUESTION: 2
You work as an Office Administrator at ABC.com. You use Microsoft Office Word 2010 to create company documents. Mia Hamm is your manager and has asked you to create a company newsletter that will be sent out to employees. The newsletter includes the text, "Please send any questions or comments to Mia Hamm." You want users to be able to click on the name "Mia Hamm" to automatically open an email addressed to [email protected]. You have already selected the name Mia Hamm. Which of the following actions should you take next?
A. You should consider inserting a Cross-reference.
B. You should consider inserting a Bookmark.
C. You should consider inserting a Hyperlink.
D. You should consider inserting a Citation.
Answer: C
NEW QUESTION: 3
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten folgende Spalten:
Sie müssen die Gesamtzahl der Kunden ermitteln, die nur Darlehenskonten haben.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
C. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
D. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
F. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
G. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
H. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
Answer: A
Explanation:
Explanation
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp