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NEW QUESTION: 1
Refer to the exhibit.

Which three command sets are required to complete this IPv6 IPsec site-to-site VTI? (Choose three.)
A. crypto isakmp-profile
match identity address ipv6 any
B. interface Tunnel0
ipv6 enable-ipsec
C. ipv6 unicast-routing
D. interface Tunnel0
tunnel mode ipsec ipv6
E. interface Tunnel0
ipv6 enable
Answer: C,D,E

NEW QUESTION: 2
Which QoS mechanism for VoIP works with weighted fair queuing (WFQ) and class-based weighted fair queuing (CBWFQ)?
A. FRF.12
B. Multilink PPP
C. IP RTP Priority and Frame Relay IP RTP Priority
D. Header compression
E. RSVP
Answer: C

NEW QUESTION: 3
Adam works as an Incident Handler for Umbrella Inc. He is informed by the senior authorities that the server of the marketing department has been affected by a malicious hacking attack. Supervisors are also claiming that some sensitive data are also stolen. Adam immediately arrived to the server room of the marketing department and identified the event as an incident. He isolated the infected network from the remaining part of the network and started preparing to image the entire system. He captures volatile data, such as running process, ram, and network connections.
Which of the following steps of the incident handling process is being performed by Adam?
A. Recovery
B. Eradication
C. Identification
D. Containment
Answer: D

NEW QUESTION: 4
Natalia Berg, CFA, has estimated the key rate durations for several maturities in three of her $25 million bond portfolios, as shown in Exhibit 1.

At a fixed-income conference in London, Berg hears a presentation by a university professor on the increasing use of the swap rate curve as a benchmark instead of the government bond yield curve. When Berg returns from the conference, she realizes she has left her notes from the presentation on the airplane. However, she is very interested in learning more about whether she should consider using the swap rate curve in her work.
As she tries to reconstruct what was said at the conference, she writes down two advantages to using the swap rate curve:
Statement 1: The swap rate curve typically has yield quotes at 11 maturities between 2 and 30 years. The
U.S. government bond yield curve, however, has fewer on-the-run issues trading at maturities of at least two years.
Statement 2: Swap curves across countries are more comparable than government bond curves because they reflect similar levels of credit risk.
Berg also estimates the nominal spread, Z-spread, and option-adjusted spread (OAS) for the Steigers Corporation callable bonds in Portfolio 2. The OAS is estimated from a binomial interest rate tree. The results are shown in Exhibit 2.

Berg determines that to obtain an accurate estimate of the effective duration and effective convexity of a callable bond using a binomial model, the specified change in yield (i.e., Ay) must be equal to the OAS.
Berg also observes that the current Treasury bond yield curve is upward sloping. Based on this observation, Berg forecasts that short-term interest rates will increase.
If the 5- and 10-year key rates increase by 20 basis points, but the 2- and 20-year key rates remain unchanged:
A. Portfolio 1 will experience the best price performance.
B. Portfolio 2 will experience the best price performance.
C. all three portfolios will experience the same price performance.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The exposure of each portfolio to changes in the 5- and 10-year rates are equal to the sum of the 5- and
10-yeat key rate durations:
portfolio 1 exposure = 0.20 + 0.15 = 0.35
portfolio 2 exposure = 0.40 + 4.00 = 4.40
Portfolio 2 has the largest exposure, and portfolio 1 has the smallest exposure. If the 5- and 10-year key rates increase, portfolio 1 will fall by the smallest amount and will experience the best price performance (i.e., the smallest decrease in value).
You can confirm this by doing the calculations for a 20 basis point increase:
% change in portfolio 1 = (-0.20 x 0.002 x 100) + (-0.15 x 0.002 x 100)
= (-0.35 x 0.002 x 100) = -0.07%
% change in portfolio 2 = (-0.40 x 0.002 x 100) + (-4.00 x 0.002 x 100)
= (-4.40 x 0.002 x 100) - -0.88%
(Study Session 14, LOS 53.f)