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NEW QUESTION: 1
Which default mail policy chain is most commonly used in Gateway placement or with 9.5+ clients?
A. Default: Legacy Clients
B. Default: Mobile
C. Default
D. Default: Standalone
Answer: C

NEW QUESTION: 2
Vault1という名前のAzure Key Vaultを含むAzureサブスクリプションがあります。
2019年1月1日、Vault1は次の秘密を保存します。

各シークレットはアプリケーションで使用できますか?回答するには、回答エリアで適切なオプションを選択します。
注:それぞれの正しい選択には1ポイントの価値があります。

Answer:
Explanation:

Explanation

Box 1: Never
Password1 is disabled.
Box 2: Only between March 1, 2019 and May 1,
Password2:

Reference:
https://docs.microsoft.com/en-us/powershell/module/azurerm.keyvault/set-azurekeyvaultsecretattribute

NEW QUESTION: 3
As part of a capacity planning exercise, a user needs a report of all Reservations for all Provisioning Groups within the user's department including the percentage used for
machine quota, memory, and storage for powered-on virtual machines.
How should the user collect the data for this report?
A. As an Enterprise Administrator, select the columns needed in the Reservation work area and export the data in a convenient form.
B. Request that the database administrator pull the data needed from the appropriate database view exporting in CSV format.
C. Request that each Provisioning Group Manager provide the Reservation data for the user's department and combine the results.
D. As an Enterprise Administrator, run the Reservation Summary Report from the Reports section in vCloud Automation Center.
Answer: A

NEW QUESTION: 4
あなたはモバイルアプリケーションをデザインする会社のために働いています。彼らはプレーヤーの記録が彼らの異なるゲームに割り当てられるサーバーを維持します。追跡システムは新しく、開発中です。
アプリケーションはEntity Frameworkを使用してAzureデータベースに接続します。データベースには、PlayerテーブルとGameテーブルがあります。
プレーヤーを追加するとき、コードは新しいプレーヤーレコードを挿入し、既存のゲームレコードと新しいプレーヤーレコードの間の関係を追加する必要があります。
アプリケーションは正しいgameIdとplayerIdを指定してCreatePlayerWithGameを呼び出し、プロセスを開始します。
(行番号は参照用にのみ含まれています。)

以下の各ステートメントについて、そのステートメントが正しい場合は「はい」を選択してください。そうでなければ、いいえを選択します。
注:それぞれ正しい選択は1ポイントの価値があります。

Answer:
Explanation:

Explanation:
Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
.HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Post)
.WithMany(p => p.PostTags)
.HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Tag)
.WithMany(t => t.PostTags)
.HasForeignKey(pt => pt.TagId);
}
}