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NEW QUESTION: 1
A security engineer is tasked with encrypting corporate email. Which of the following technologies provide the MOST complete protection? (Select TWO)
A. Secure POP3
B. IPSEC
C. HMAC
D. IMAP
E. PGP/GPG
F. S/MIME
Answer: C,F
NEW QUESTION: 2
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, die dasselbe Szenario verwenden. Zur Vereinfachung wird das Szenario in jeder Frage wiederholt. Jede Frage stellt ein anderes Ziel und eine andere Antwortauswahl dar, aber der Text des Szenarios ist in jeder Frage dieser Reihe genau gleich.
Ihr Netzwerk enthält eine Active Directory-Domäne mit dem Namen contoso.com. Die Funktionsebene der Domäne ist Windows Server 2012.
Das Netzwerk verwendet einen Adressraum von 192.168.0.0/16 und enthält mehrere Subnetze.
Das Netzwerk ist nicht mit dem Internet verbunden.
Die Domäne enthält drei Server, die wie in der folgenden Tabelle gezeigt konfiguriert sind.
Clientcomputer beziehen TCP / IP-Einstellungen von Server3.
Sie fügen Server2 einen zweiten Netzwerkadapter hinzu. Sie verbinden den neuen Netzwerkadapter mit dem Internet. Sie installieren den Routing-Rollendienst auf Server2.
Server1 verfügt über vier DNS-Zonen, die wie in der folgenden Tabelle gezeigt konfiguriert sind.
Sie müssen eine Zone erstellen, um sicherzustellen, dass Server1 Namen mit einfacher Bezeichnung auflösen kann.
Wie soll die Zone auf Server1 benannt werden?
A. NetBIOS
B. GEWINNT
C. . (Wurzel)
D. GlobalNames
Answer: D
Explanation:
https://technet.microsoft.com/en-us/library/cc816610(v=ws.10).aspx
NEW QUESTION: 3
Refer to the exhibit. EIGRP has been configured on all routers in the network. The command metric weights 0 0 1 0 0 has been added to the EIGRP process so that only the delay metric is used in the path calculations. Which router will R1 select as the successor and feasible successor for Network A?
A. R2 becomes the successor and will be placed in the routing table. No feasible successor will be selected as the reported distance from R4 is lower than the feasible distance.
B. R4 becomes the successor for Network A and will be included in the routing table. No feasible successor will be selected as the advertised distance from R2 is higher than the feasible distance.
C. R4 becomes the successor for Network A and will be placed in the routing table. R2 becomes the feasible successor for Network A.
D. R2 becomes the successor and will be placed in the routing table. R4 becomes the feasible successor for Network A.
Answer: B
Explanation:
The point of the question is DUAL of EIGRP. FD=5+10+5=20 R4 is successor No FS, because no other router's AD is lower the FD