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NEW QUESTION: 1
Middleware is best described as
A. the process Pathsend servers use for link requests in a Pathway environment
B. software between two application server processes
C. software an application uses to receive services from an operating system
D. software an application programmer writes to access privileged procedures
Answer: C
NEW QUESTION: 2
Which three parameters must match to establish OSPF neighbor adjacency? (Choose three.)
A. the process ID
B. the subnet mask
C. the hello interval
D. authentication
E. the OSPF interface priority
F. the router ID
Answer: B,C,D
Explanation:
Explanation/Reference:
Explanation:
NEW QUESTION: 3
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, die dasselbe Szenario darstellen. Jede Frage in der Reihe enthält eine eindeutige Lösung, mit der die angegebenen Ziele erreicht werden können. Einige Fragensätze haben möglicherweise mehr als eine richtige Lösung, während andere möglicherweise keine richtige Lösung haben.
Nachdem Sie eine Frage in diesem Abschnitt beantwortet haben, können Sie NICHT mehr darauf zurückgreifen. Infolgedessen werden diese Fragen nicht im Überprüfungsbildschirm angezeigt.
Sie haben eine virtuelle Azure-Maschine mit dem Namen VM1. VM1 wurde mithilfe einer benutzerdefinierten Azure Resource Manager-Vorlage mit dem Namen ARM1.json bereitgestellt.
Sie erhalten eine Benachrichtigung, dass VM1 von der Wartung betroffen ist.
Sie müssen VM1 sofort auf einen anderen Host verschieben.
Lösung: Klicken Sie im Update Management Blade auf Aktivieren.
Erfüllt dies das Ziel?
A. Ja
B. Nein
Answer: B
Explanation:
You would need to Redeploy the VM.
References: https://docs.microsoft.com/en-us/azure/virtual-machines/windows/redeploy-to-new-node
NEW QUESTION: 4
「MyController」という名前のカスタムコントローラの正確なコンストラクタは何ですか？
A. public MyController（List objects）{accounts =（List）objects; }
B. public MyController（ApexPages.StandardController stdController）{account =（Account）stdController.getRecord（）; }
C. public MyController（sObject obj）{account =（Account）obj; }
D. public MyController（）{account = new Account（）; }
Answer: D