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NEW QUESTION: 1
You are asked to identify a feature of the Open Value Subscription program which meets the business goals of Windaus Press. Of the following features, which feature should you choose?
A. Standardize the version of applications on all company desktops
B. Non-perpetual licenses
C. Ability to modify the number of licenses
D. Standardize the version of operating systems on all company desktops
Answer: D

NEW QUESTION: 2
Which options are offered in HPE Foundation Care services? (Select two.)
A. access to firmware and software updates
B. pre-failure alerts on covered options
C. Single-point contact through problem resolution
D. third-party OS support collaboration
E. health check on covered devices
Answer: A,C
Explanation:
Explanation/Reference:
Explanation:
A: Foundation Care Services include
* One place to call for all your software issues
Let us simplify your support with one place to call for hardware and software so you can save time and get more done.
D: Make HP your first call for help
With HP Foundation Care, you'll have access to HP experts via phone, web, or both. You'll receive problem diagnosis and support, replacement parts and materials, access to firmware and software updates, and collaborative support on leading third party operating systems for x86 hardware.
References: http://www8.hp.com/se/sv/business-services/it-services/foundation-care-services.html

NEW QUESTION: 3
View the Exhibit and examine the structure of ORDERS and CUSTOMERS tables. There is only one customer with the cus_last_name column having value Roberts. Which INSERT statement should be used to add a row into the ORDERS table for the customer whose CUST_LAST_NAME is Roberts and CREDIT_LIMIT is 600?

A. INSERT INTO(SELECT o.order_id. o.order_date.o.order_modex.customer_id. o.ordertotal FROM orders o. customers c WHERE o.customer_id = c.customerid AND c.cust_la$t_name-RoberTs' ANDc.credit_liinit=600)
VALUES (L'10-mar-2007\ 'direct'.( SELECT customer_id
FROM customers
WHERE cust_last_iiame='Roberts' AND
credit_limit=600). 1000);
B. INSERT INTO orders VALUES (l.'10-mar-2007\ 'direct'. (SELECT customerid FROM customers WHERE cust_last_iiame='Roberts' AND credit_limit=600). 1000);
C. . INSERT INTO orders (order_id.order_date.order_mode. (SELECT customer id FROM customers WHERE cust_last_iiame='Roberts' AND redit_limit=600).order_total)
VALUES(L'10-mar-2007'. 'direct', &&customer_id, 1000):
D. INSERT INTO orders (order_id.order_date.order_mode.
(SELECT customer_id
FROM customers
WHERE cust_last_iiame='Roberts' AND
credit_limit=600).order_total)
VALUES(l.'10-mar-2007\ 'direct'. &customer_id. 1000)
Answer: B