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NEW QUESTION: 1
You manage a deployment of Microsoft System Center 2012 R2 Configuration Manager.
From the Configuration Manager console, you discover that three client computers failed the client check.
You identify that the issue is related to WMI service corruption.
You manually repair WMI on the client computers.
You need to trigger a client health auto-remediation on the three client computers as soon as possible.
What should you do?
A. On the client computers, run the Machine Policy Retrieval & Evaluation Cycle action.
B. On the client computers, start a Configuration Manager Health Evaluation scheduled task.
C. From the Configuration Manager console, schedule a client status update.
D. From the Configuration Manager console, restart the
SMS_SITE_SYSTEM_STATUS_SUMMARIZER component.
Answer: B
NEW QUESTION: 2
Which statement correctly describes GoldenGate Extract and Replicat process reports?
A. By default process reports are named for the Extract or Replicat group and up to 10 old reports are kept.
B. By default process reports are named for the Extract or Replicat group and up to 99 old reports can be saved depending on the REPORTUM parameter.
C. Process reports take the name set by the optional report parameter of the ADD extract replicat command and up to 99 old reports can be saved depending on the REPORTNUM parameter.
D. Process reports take the name set by the required report file parameters and up to 10 old reports will be saved.
Answer: D
Explanation:
http://download.oracle.com/docs/cd/E15881_01/doc.104/gg_wux_ref_v104.pdf
NEW QUESTION: 3
Under which circumstance should a network administrator implement one-way NAT?
A. when the network must route UDP traffic
B. when traffic that originates inside the network must be routed to internal hosts
C. when the network has few public IP addresses and many private IP addresses require outside access
D. when traffic that originates outside the network must be routed to internal hosts
Answer: D
Explanation:
NAT operation is typically transparent to both the internal and external hosts. Typically the internal host is aware of
the true IP address and TCP or UDP port of the external host. Typically the NAT device may function as the default
gateway for the internal host. However the external host is only aware of the public IP address for the NAT device and
the particular port being used to communicate on behalf of a specific internal host.
NAT and TCP/UDP
"Pure NAT", operating on IP alone, may or may not correctly parse protocols that are totally concerned with IP
information, such as ICMP, depending on whether the payload is interpreted by a host on the "inside" or "outside" of
translation. As soon as the protocol stack is traversed, even with such basic protocols as TCP and UDP, the protocols
will break unless NAT takes action beyond the network layer.
IP packets have a checksum in each packet header, which provides error detection only for the header. IP datagrams
may become fragmented and it is necessary for a NAT to reassemble these fragments to allow correct recalculation of
higher-level checksums and correct tracking of which packets belong to which connection.
The major transport layer protocols, TCP and UDP, have a checksum that covers all the data they carry, as well as the
TCP/UDP header, plus a "pseudo-header" that contains the source and destination IP addresses of the packet carrying
the TCP/UDP header. For an originating NAT to pass TCP or UDP successfully, it must recompute the TCP/UDP header
checksum based on the translated IP addresses, not the original ones, and put that checksum into the TCP/UDP
header of the first packet of the fragmented set of packets. The receiving NAT must recompute the IP checksum on
every packet it passes to the destination host, and also recognize and recompute the TCP/UDP header using the
retranslated addresses and pseudo-header. This is not a completely solved problem. One solution is for the receiving
NAT to reassemble the entire segment and then recompute a checksum calculated across all packets.
The originating host may perform Maximum transmission unit (MTU) path discovery to determine the packet size that
can be transmitted without fragmentation, and then set the don't fragment (DF) bit in the appropriate packet header
field. Of course, this is only a one-way solution, because the responding host can send packets of any size, which may
be fragmented before reaching the NAT.
NEW QUESTION: 4
情報システムへの不正アクセスを発見するために使用できる探知制御は次のうちどれですか？
A. システムアクセスに長くて複雑なパスワードが必要
B. マルチアクター認証によるデータセンターへのアクセスの保護
C. セキュリティ情報およびイベント管理（SIEM）システムの実装
D. システムアクセスログのペノディックレビューを実行するために内部監査を要求する
Answer: C