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NEW QUESTION: 1
For which reason is the lack of portability a significant advantage for desktop PCs?
A. low TCO
B. Flexibility
C. security
D. high performance
Answer: C
Explanation:
Desktops are not portable. Not portable at all. And this is a good thing when it comes to security and durability.
Reference:http://jalapeno.is/asking-if-the-world-can-live-without-the-desktop-pc/(SeeDesktop are Secure and they last along time, 1stLine).
NEW QUESTION: 2
You are in the process of troubleshooting the Contact Center License Manager.
You must confirm that the server identified in the Contact Center License Manager Registry key matches the Contact Center License Manager server configured in which utility?
A. server configuration
B. Contact center Management
C. Access and partition Manager
D. Multimedia Administration Tool
Answer: C
NEW QUESTION: 3
DRAG DROP
Your network contains two servers named Server1 and Server2 that run Windows Server 2012. Server1 and Server2 have the Hyper-V server role installed and are members of a failover cluster.
The network contains a Storage Area Network (SAN) that has a LUN named LUN1. LUN1 is connected to a 12-TB disk on the SAN.
You plan to host three new virtual machines on the failover cluster. Each virtual machine will store up to 4 TB of data on a single disk. The virtual machines will be backed up from the hosts by using the Volume Shadow Copy Service (VSS).
You need to ensure that Server1 and Server2 can store the new virtual machines on the SAN.
Which three actions should you perform?
To answer, move the three appropriate actions from the list of actions to the answer area and arrange them in the correct order.
Select and Place:
Answer:
Explanation:
Explanation/Reference:
Explanation:
http://technet.microsoft.com/en-us/library/hh831446.aspx
NEW QUESTION: 4
SIMULATION
What is the output of the following code?
class Number {
private $v = 0;
public function __construct($v) { $this->v = $v; }
public function mul() {
return function ($x) { return $this->v * $x; };
}
}
$one = new Number(1);
$two = new Number(2);
$double = $two->mul()->bindTo($one);
echo $double(5);
Answer:
Explanation:
5