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NEW QUESTION: 1
You have a System Center 2012 Service Manager infrastructure and a System Center 2012 Operations Manager infrastructure. You enable the Alert Connector in Service Manager. Operations Manager has the Microsoft SQL Server Monitoring Management Pack installed. You plan to configure the Alert Connector to receive SQL Server alerts from Operations Manager.
You need to prepare the Service Manager infrastructure for the planned configuration. Which two tasks should you perform? (Each correct answer p resents a complete solution. Choose two.)
A. Create a notification channel.
B. Install the SQL Server Notification Services.
C. Create a runbook.
D. Import the SQL Server Management Pack.
E. Create an incident template.
F. Enable the Operations Manager CI connector.
Answer: D,F
Explanation:
Explanation/Reference:
Explanation:
B: In System Center 2012 ?Service Manager, there are two types of connectors for System Center Operations Manager. You use the first type of connector, the alert connector, to automatically generate incidents that are based on Operations Manageralerts. You use the second type of connector, the configuration item (CI) connector, to import discovered objects from Operations Manager as configuration items into the Service Manager database.
C:
* You must import some System Center Operations Manager management packs into Service Manager.
When you install Service Manager, a set of System Center Operations Manager management packs for common objects and the required Windows PowerShell scripts are copied to your Service Manager installation folder.
* For the Operations Manager CI connector to function correctly, you have to import a set of management packs into Service Manager.
http://technet.microsoft.com/en-us/library/hh524325.aspx
NEW QUESTION: 2
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: B
Explanation:
Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 , 8, 4, 2, 1 Add them up and you get 255. Add one for the all zeros option, and the total is 256. Now take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear, in which case you could conceivably have 255. The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of networks are 2