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NEW QUESTION: 1
SAP HANA on Azure（ラージインスタンス）をAzure Log Analyticsワークスペースに接続する必要があります。
どの4つのアクションを順番に実行する必要がありますか？回答するには、適切なアクションをアクションのリストから回答領域に移動し、正しい順序に並べます。
Answer:
Explanation:
Explanation:
手順1：Azure拡張監視をインストールします。
SAP Azure拡張監視拡張機能を使用すると、SAPワークロードを実行しているAzure VMから、OSやアプリケーションのパフォーマンスカウンターなどの診断データを収集できます。
ステップ2：Log AnalyticsクライアントをSAP HANA on Azure（ラージインスタンス）インスタンスにインストールします。
手順3：仮想ネットワークでLog Analyticsゲートウェイを構成します。
ステップ4：ゲートウェイで実行します。
参照：
http://www.deployazure.com/compute/virtual-machines/sap-azure-enhanced-monitoring-extension/
https://docs.microsoft.com/en-us/azure/azure-monitor/platform/gateway
NEW QUESTION: 2
Which is the CORRECT approach for managing a large improvement initiative as smaller iterations?
A. Feedback should only be taken into account when one iteration fails to meet its objective
B. Each iteration should be designed before starting the initiative and implemented without feedback
C. Feedback should be reduced for large improvements as it is unlikely that circumstances will change
D. Each iteration should be continually re-evaluated based on feedback
Answer: D
NEW QUESTION: 3
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 8 kHz x 8-bit code words
B. 2 x 8 kHz x 4-bit code words
C. 2 x 4-bit code words x 8 kHz
D. 2 x 4 kHz x 8-bit code words
Answer: D
Explanation:
Explanation/Reference:
Explanation:
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400 Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for voice is 4000 Hz. According to Nyquist theory, we must double the highest frequency, so 2x4kHz = 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second = 64 Kilobit per second = 64 Kbps) Reference: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency must be greater than twice the bandwidth of the input signal in order to be able to reconstruct the original perfectly from the sampled version."