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NEW QUESTION: 1
Drag and drop the characteristics from the left onto the correct routing protocol types on the right.
Answer:
Explanation:
Explanation
OSPF: SEGMENT, LINK STATE, TABLES
EIGRP: UNEQUAL PATH, DISTANCE VECTOR, METRIC
NEW QUESTION: 2
Given the SAS data set WORK.ORDERS:
The variable Order_id is numeric; Customer is character; and Ship_date is a numeric containing a SAS date value.
A programmer would like to create a new variable called Note, that shows a character value with the Order_id and Ship_date shown with a date9. format. For the first observation, Note would look like the following: "Order 9341 shipped on 02FEB2009".
Which of the following statement will correctly create the value and assign it to Note?
A. note=catx(' ','Order',order_id,'shipped on',input(ship_date,date9.));
B. note=catx(' ','Order',order_id,'shipped on',transwrd(ship_date,date9.));
C. note=catx(' ','Order',order_id,'shipped on',put(ship_date,date9.));
D. note=catx(' ','Order',order_id,'shipped on',char(ship_date,date9.));
Answer: C
NEW QUESTION: 3
For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
NEW QUESTION: 4
Given the following two tables:
TAB1
COL_1 COL_2
A 10 B 12 C 14
TAB2
COL_A COL_B
A 21 C 23 D 25
Assuming the following results are desired:
COL_1 COL_2 COL_A COL_B A 10 A 21 B 12 - C 14 C 23 - - D 25
Which of the following joins will produce the desired results?
A. SELECT * FROM tab1 FULL OUTER JOIN tab2 ON col_1 =col_a
B. SELECT * FROM tab1 INNER JOIN tab2 ON col_1 =col_a
C. SELECT * FROM tab1 RIGHT OUTER JOIN tab2 ON col_1 =col_a
D. SELECT * FROM tab1 LEFT OUTER JOIN tab2 ON col_1 =col_a
Answer: A